9/y^2+8/y

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Solution for 9/y^2+8/y equation:


D( y )

y = 0

y^2 = 0

y = 0

y = 0

y^2 = 0

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in (-oo:0) U (0:+oo)

8/y+9/(y^2) = 0

8*y^-1+9*y^-2 = 0

t_1 = y^-1

9*t_1^2+8*t_1^1 = 0

9*t_1^2+8*t_1 = 0

DELTA = 8^2-(0*4*9)

DELTA = 64

DELTA > 0

t_1 = (64^(1/2)-8)/(2*9) or t_1 = (-64^(1/2)-8)/(2*9)

t_1 = 0 or t_1 = -8/9

t_1 = -8/9

y^-1+8/9 = 0

1*y^-1 = -8/9 // : 1

y^-1 = -8/9

-1 < 0

1/(y^1) = -8/9 // * y^1

1 = -8/9*y^1 // : -8/9

-9/8 = y^1

y = -9/8

t_1 = 0

y^-1+0 = 0

y^-1 = 0

1*y^-1 = 0 // : 1

y^-1 = 0

y naleu017Cy do O

y = -9/8

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